Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
if the sum of two numbers is 3 then the maximum value of the product of the first and the square of second is
hi, let one no. be a (0=< a = <3 ) other no. will be 3- a so, we have to maximize (3-a ) * a^2 let p = (3-a ) * a^2 dp/da = 6a - 3a^2 = 0 emplies, either a= 0 , or a =2 d^2 p / da^2 = 6 - 6a so, at a = 0 , we will have a min . (d^2 p / da^2 >0 ) d^3 p / da^3 = -6 emplies that at a= 2 we will get a max. so the max. value will be 4.
hi,
let one no. be a (0=< a = <3 )
other no. will be 3- a
so, we have to maximize (3-a ) * a^2
let p = (3-a ) * a^2
dp/da = 6a - 3a^2
= 0
emplies, either a= 0 , or
a =2
d^2 p / da^2 = 6 - 6a
so, at a = 0 , we will have a min . (d^2 p / da^2 >0 )
d^3 p / da^3 = -6 emplies that at a= 2 we will get a max.
so the max. value will be 4.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -