The range of the function ƒ(x)=sin(sin-1{x}) where {.} is fractional part of x, is............

Hi,

this is very easy ,if u  think logically  

the range of {x} =(0,1) 

sin inverse of {x} will giv the value of theta    (sine of which is 0 to 1 ,leaving the 0 & 1 both)

now sine of that theta will be (0,1)

other way u can look that sin(sin^-1(x)) = x   if x = [0,1] & {x} = ( 0,1)  which is subset of [0,1]

GOOD LUCK