If &fnof;(x) is continuous function for all xεR and the range of &fnof;(x)=(2,√26) and g(x)=[&fnof;(x)/a] is continuous for all xεR. Then least positive integral value of a is..........

Question

If &fnof;(x) is continuous function for all x&epsilon;R and the range of &fnof;(x)=(2,&radic;26) and g(x)=[&fnof;(x)/a] is continuous for all x&epsilon;R. Then least positive integral value of a is..........

anandpal shekhawat · Answer

hi, as f(x) is continuous for all values of x. so, g(x) will be also continuous if g(x) = f(x) as we have to find min +ve integral value of a for which g(x) is continuous so, it will be 1 hence a = 1 is ans.

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If ƒ(x) is continuous function for all xεR and the range of ƒ(x)=(2,√26) and g(x)=[ƒ(x)/a] is continuous for all xεR. Then least positive integral value of a is..........

If ƒ(x) is continuous function for all xεR and the range of ƒ(x)=(2,√26) and g(x)=[ƒ(x)/a] is continuous for all xεR. Then least positive integral value of a is..........

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