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The number of roots of the equation, cot x=π/2+x in [-π,3π/2] is,

The number of roots of the equation,


cot x=π/2+x in [-π,3π/2] is,

Grade:12

1 Answers

anandpal shekhawat
8 Points
12 years ago
hi, put x = cot^-1(#) so, it becomes # = pie/2 + cot^-1(#) & #-pie/2 = cot^-1(#) # = -cot{pie/2 - #} implies # = -tan(#) & from above # = cotx implies cotx = -tan(cotx) in above domain this eqn is satisfied by x = {-pie/2, pie/2, 3pie/2} so no. of roots are 3.

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