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Grade: 12
        

The number of roots of the equation,


cot x=π/2+x in [-π,3π/2] is,

10 years ago

Answers : (1)

anandpal shekhawat
8 Points
							hi,
put x = cot^-1(#)
  so, it becomes
  # = pie/2 + cot^-1(#)
 &  #-pie/2 = cot^-1(#)
  # = -cot{pie/2 - #}
implies # = -tan(#)
 & from above # = cotx
 implies cotx = -tan(cotx)
 in above domain this eqn is satisfied by
  x = {-pie/2, pie/2, 3pie/2}
so no. of roots are 3.
						
10 years ago
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