Grade 12Differential Calculus
The number of roots of the equation,
cot x=π/2+x in [-π,3π/2] is,
The number of roots of the equation,
cot x=π/2+x in [-π,3π/2] is,
1 Answer
anandpal shekhawat
hi,
put x = cot^-1(#)
so, it becomes
# = pie/2 + cot^-1(#)
& #-pie/2 = cot^-1(#)
# = -cot{pie/2 - #}
implies # = -tan(#)
& from above # = cotx
implies cotx = -tan(cotx)
in above domain this eqn is satisfied by
x = {-pie/2, pie/2, 3pie/2}
so no. of roots are 3.
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