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let, lim x tends to zero sin2x/tan(x/2)=L1,AND lim x tends to zero e2x-1/x=L2 , then what is value of L1L2 ?
limit x tends to zero sin2x/tan(x/2)
=lim x tends to zero [(x/2)(2x)sin2x]/[(x/2)(2x)tan(x/2)]
=lim x tends to zero [2x/(x/2)].........(since lim x tends to zero (sinx)/x=1 and lim x tends to zero (tanx)/x=1)
=4.
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