Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

let [root(n 2 +1)]=[root(n 2 +λ)] , where n, λ€N . show that λ can have 2n different values.

let [root(n2+1)]=[root(n2+λ)] , where n, λ€N . show that λ can have 2n different values.

Grade:

1 Answers

mycroft holmes
272 Points
11 years ago

for 1≤ λ≤ 2n we have n2< n2+λ<(n+1)2

 

Hence n < √(n2+λ) < (n+1) and hence we have [√(n2+λ)] = [√(n2+1)] = n

 

If λ≤0 or λ>2n,  [√(n2+λ)] ≠ n

 

So these are the 2n values of λ for which the given equation holds

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free