Flag Differential Calculus> domain...
question mark

root(1-root(1-root(2-x2)))

anurag singhal , 15 Years ago
Grade
anser 2 Answers
Pratham Ashish

Last Activity: 15 Years ago

hi ,

 for  root(2-x2) to be real we must have x^2=<2 emplies  that

x ε [-root2 , root 2]

then, for (1-root(2-x2) to be real , root(2-x2)=<1 , emplies (2-x2)=<1

x^2 >= 1  so , x ε [-root2 , -1 ] U [1, root2 ]

 we need not further analysis becoz   root(1-root(2-x2)) will always less than 1

so, the domain will be     x ε [-root2 , -1 ] U [1, root2 ]

 

RAHUL GAUR

Last Activity: 14 Years ago

-2<=x<=-1 and 1<=x<=2

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...