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f(x)=root(2{x} 2 -3{x}+1) x belongs to [-1,1], where {...} denotes fractional part of x
root[2{x}2-3{x}+1]=f(x) 2{x}2-3{x}+1 ≥ 0 =>[2{x}-1] [{x}-1] ≥0 we know that {x}≠1 =>[2{x}-1]≥0 1/2≤x<3/2 but x belongs to [-1,1] =>x € [1/2 , 1)
root[2{x}2-3{x}+1]=f(x)
2{x}2-3{x}+1 ≥ 0 =>[2{x}-1] [{x}-1] ≥0
we know that {x}≠1
=>[2{x}-1]≥0
1/2≤x<3/2
but x belongs to [-1,1]
=>x € [1/2 , 1)
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