Differential Calculus
f(x)=root(2{x}2-3{x}+1)
x belongs to [-1,1], where {...} denotes fractional part of x
f(x)=root(2{x}2-3{x}+1)
x belongs to [-1,1], where {...} denotes fractional part of x
1 Answer
Vanya Saxena
root[2{x}2-3{x}+1]=f(x)
2{x}2-3{x}+1 ≥ 0 =>[2{x}-1] [{x}-1] ≥0
we know that {x}≠1
=>[2{x}-1]≥0
1/2≤x<3/2
but x belongs to [-1,1]
=>x € [1/2 , 1)
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