f(x)=root(2{x} 2 -3{x}+1) x belongs to [-1,1], where {...} denotes fractional part of x

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Vanya Saxena · Answer

root[2{x} 2 -3{x}+1]=f(x) 2{x} 2 -3{x}+1 &ge; 0 =>[2{x}-1] [{x}-1] &ge;0 we know that {x}&ne;1 =>[2{x}-1]&ge;0 1/2&le;x<3/2 but x belongs to [-1,1] =>x &euro; [1/2 , 1 )

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f(x)=root(2{x} 2 -3{x}+1) x belongs to [-1,1], where {...} denotes fractional part of x

f(x)=root(2{x}²-3{x}+1)

x belongs to [-1,1], where {...} denotes fractional part of x

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f(x)=root(2{x} 2 -3{x}+1) x belongs to [-1,1], where {...} denotes fractional part of x

f(x)=root(2{x}2-3{x}+1) x belongs to [-1,1], where {...} denotes fractional part of x

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f(x)=root(2{x}²-3{x}+1)

x belongs to [-1,1], where {...} denotes fractional part of x