badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 

                        
let [root(n 2 +1)]=[root(n 2 +λ)] , where n, λ€N . show that λ can have 2n different values.
11 years ago

Answers : (1)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points 
							
Hello
Well for [root(n^2+1)] =n for any n greater than 0
n^2+lamda should between n^2 and (n+1)^2
=> (n+1)^2-n^2=2n+1 if we include 0
So it can have 2n+1 different values
take 2,3
9-4=5 which is 2*2+1 if we include 0
Thanks & Regards
Arun Kumar
Btech IIT delhi
Askiitians Faculty
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Differential Calculus

Find the particular integral of 1. (D-2)^4=x^3 e^2x 2. (D^2+4D-12)y=(x-1)e^2x Answer & Earn Cool Goodies
If f(x)=sinx then find (fofof)(a) where a belongs to [0, pi/2] and d/dx(fofof)^x |x=a Answer & Earn Cool Goodies
How to solve 1power infinity forms in limits and continuity sums. Please explain me
\lim_(x->\infty )(1+(1)/(2x-2))^(x-1) without using L hospital rule
Why we have to take x^2 as (1-h)^2 and (1+h)^2.....and how we have to take
View all Questions »


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details