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let [root(n 2 +1)]=[root(n 2 +λ)] , where n, λ€N . show that λ can have 2n different values. let [root(n2+1)]=[root(n2+λ)] , where n, λ€N . show that λ can have 2n different values.
let [root(n2+1)]=[root(n2+λ)] , where n, λ€N . show that λ can have 2n different values.
HelloWell for [root(n^2+1)] =n for any n greater than 0n^2+lamda should between n^2 and (n+1)^2=> (n+1)^2-n^2=2n+1 if we include 0So it can have 2n+1 different valuestake 2,39-4=5 which is 2*2+1 if we include 0Thanks & RegardsArun KumarBtech IIT delhiAskiitians Faculty
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