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Differential Calculus

if {x} and [x] represent fractional and intergral part of x , then find the value of

[x]+ 2000∑r=1{x+r}/2000

Profile image of anurag singhal
16 Years agoGrade
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1 Answer

Profile image of askiitian.expert- chandra sekhar
16 Years ago

Hi anurag,

[x]+ 2000∑r=1{x+r}/2000

since {1+x}={x}

{2+x}={x}

{3+x}={x}

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{r+x}={x}

 the equation becomes,[x]+{x}×2000/2000 =[x] + {x} =x