hi, i hv doubt for below question:
find natural number a such that:
sum[f(a+k)] for k=1,n = 16(2^n-1)
where f(x+y)=f(x).f(y) for all natural x,y and f(1)=2.
note:I was able to find out that f(x)=2^x here but not able to proceed further. Please suggest.
thanks
hi, i hv doubt for below question:
find natural number a such that:
sum[f(a+k)] for k=1,n = 16(2^n-1)
where f(x+y)=f(x).f(y) for all natural x,y and f(1)=2.
note:I was able to find out that f(x)=2^x here but not able to proceed further. Please suggest.
thanks