x= exp(tan^-1(y-x^2)/x^2 then dy/dx

notex^2 means x square

Take natural logarithm both sides and solve.

Proceed using the method , I will help you along.

x= exp(tan^-1(y-x^2)/x^2)

first simplyfy this

take log both side

lnx =tan^-1(y-x^2)/x^2

or tan(lnx)=(y-x^2)/x^2

or 1+tan(lnx) =y/x²

or y= x² +x²tan(lnx)

now differntiate

dy/dx=2x +x sec²(lnx) +2x tan(lnx)

that is tha final answer