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| x| <1;let y =1+x+x^2+…………to infinity then dy/dx equal to
note x^2 means x square
1+x+x^2+... =1/(1-x). (It is an infinite geometric series and given mod(x) < 1)
y=1/(1-x),
dy/dx = {(1-x)0 - 1(-1)}/(1-x)^2
= 1/(1-x)^2
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