Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
For x ? R, lim n→∞ ((x-3)/(x+2)) x = (A) e (B) e -1 (C) e -5 (D) e 5 For x ? R, limn→∞((x-3)/(x+2))x = (A) e (B) e-1 (C) e-5 (D) e5
For x ? R, limn→∞((x-3)/(x+2))x = (A) e (B) e-1 (C) e-5 (D) e5
Hi Pallavi, y=limx→∞((x-3)/(x+2))x =limx→∞((1-3/x)/(1+2/x))x 1∞ form log y = log limx→∞((x-3)/(x+2))x y = elimx→∞xlog((1-3/x)/(1+2/x)) y = elimx→∞[log((1-3/x)/(1+2/x))]/(1/x) y = elimx→∞[log((1-3/x)- log(1+2/x))]/(1/x) y =elimx→∞{[-3log((1-3/x)]/(-3/x)- [2log(1+2/x))](2/x)} y = e-3-2 = e-5
Hi Pallavi,
y=limx→∞((x-3)/(x+2))x
=limx→∞((1-3/x)/(1+2/x))x
1∞ form
log y = log limx→∞((x-3)/(x+2))x
y = elimx→∞xlog((1-3/x)/(1+2/x))
y = elimx→∞[log((1-3/x)/(1+2/x))]/(1/x)
y = elimx→∞[log((1-3/x)- log(1+2/x))]/(1/x)
y =elimx→∞{[-3log((1-3/x)]/(-3/x)- [2log(1+2/x))](2/x)}
y = e-3-2 = e-5
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -