If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation :
(A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2
(C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4

Question

If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation : (A) 0 &le; M &le; 1 (B) 1 &le; M &le; 2 (C) 2 &le; M &le; 3 (D) 3 &le; M &le; 4

askiitian.expert- chandra sekhar · Answer

Hi pallavi, {(a+b)+(c+d)}/2 &ge;&radic;{(a+b)(c+d) since A.M>G.M 2/2 &ge; &radic;M &radic;M &le; 1 0&le; M &le; 1

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If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation : (A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2 (C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4

If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation :
(A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2
(C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4

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If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation : (A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2 (C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4

If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation : (A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2 (C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4

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If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation :
(A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2
(C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4