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If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisfies the relation : (A) 0 ≤ M ≤ 1 (B) 1 ≤ M ≤ 2 (C) 2 ≤ M ≤ 3 (D) 3 ≤ M ≤ 4
Hi pallavi, {(a+b)+(c+d)}/2 ≥√{(a+b)(c+d) since A.M>G.M 2/2 ≥ √M √M ≤ 1 0≤ M ≤ 1
Hi pallavi,
{(a+b)+(c+d)}/2 ≥√{(a+b)(c+d) since A.M>G.M
2/2 ≥ √M
√M ≤ 1
0≤ M ≤ 1
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