Y=ƒ(2x-1)/(x^2+1)ƒ(x)= sin(x^2 )Then dy/dx . ..{note x^2 means xsquare}

Taking u r question to be :

f(x) = sin(x²) and y=f(2x-1)/(x²+1)

so y = sin((2x-1)²) / (x²+1)

dy/dx ={ 4.(2x-1).(x²+1).cos((2x-1)²) ^_ 2x.sin((2x-1)²) } / (x²+1)

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