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Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2 Then dy/dx

Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2
Then dy/dx

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1 Answers

Ramesh V
70 Points
12 years ago

please post question clearly

regards

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