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if 8ƒ(x)=6ƒ(1/x)=x+5and y=x^2ƒ(x)then find the value of of dy/dx at x=1 plz sir make me understand this question step by step note x^2 means x square
I'll take the question to be : 8ƒ(x)+6ƒ(1/x)=x+5 ........(1) now put 1/x for x , we get -> 8ƒ(1/x)+6ƒ(x)=(1/x)+5 ....(2) on solving, we'll get f(x) = { 4x -(3/x)+5 } / 14 so Y = x2/14* (4x -(3/x)+5 ) dy/dx = (12x2 + 10x -3)/14 dy/dx at x=1 is 19/14
I'll take the question to be :
8ƒ(x)+6ƒ(1/x)=x+5 ........(1)
now put 1/x for x , we get -> 8ƒ(1/x)+6ƒ(x)=(1/x)+5 ....(2)
on solving, we'll get f(x) = { 4x -(3/x)+5 } / 14
so Y = x2/14* (4x -(3/x)+5 )
dy/dx = (12x2 + 10x -3)/14
dy/dx at x=1 is 19/14
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