Learn to Create a Robotic Device Using Arduino in the Free Webinar. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on Robotics (Block Chain) Learn to create a Robotic Device Using Arduino
30th Jan @ 5:00PM for Grade 1 to 10
Let f(x) = (2x-pie) 3 +2x - cosx. Then show that d[ f -1 (x)] / dx at x=pie/2 is 1/3. Let f(x) = (2x-pie) 3 +2x - cosx. Then show that d[ f -1 (x)] / dx at x=pie/2 is 1/3.
Let f(x) = (2x-pie) 3 +2x - cosx. Then show that d[ f -1 (x)] / dx at x=pie/2 is 1/3.
(1) It's "Pi". and Pi is not 22/7 first find df(x) / dx. df(x)/dx = 3(2x - pi)2 * 2 + 2 + sin(x) =6(2x - pi)2 + 2 + sin(x) Let x = pi/2 , we get: 0 + 2 + 1 = 3 So the answer for df-1(x)/dx i.e., 1/[df(x)/dx] is : 1/3 -- Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Naga Ramesh IIT Kgp - 2005 batch
(1) It's "Pi". and Pi is not 22/7
first find df(x) / dx. df(x)/dx = 3(2x - pi)2 * 2 + 2 + sin(x)
=6(2x - pi)2 + 2 + sin(x) Let x = pi/2 , we get: 0 + 2 + 1 = 3 So the answer for df-1(x)/dx i.e., 1/[df(x)/dx] is : 1/3
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Naga Ramesh IIT Kgp - 2005 batch
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -