Find the derivatives of this function

In(ye^x)=3

ln(ye^x)=3

ye^x=e^3  (as per the property, log_ea=b means a=e^b )

now, y=e^(3-x)

dy/dx=e^(3-x)d(3-x)/dx  (using chain rule)

:. dy/dx=-e^(3-x)

hope this helps....;)

ln(ye^x)=3

=>  lny + lne^x =3 (using property)

=>  lny + x*lne =3

=> lny + x =3    (lne=1; using property-same baseand no.)

now diff;

dy/dx*1/y  +1 =0

so dy/dx= -y

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