find the equation of the tangent to the curveexy=x+(In y)2 at the point (0,e)
ilham rafie , 13 Years ago
Grade
Differential Calculus> HW 3...
1 Answers
Chetan Mandayam Nayakar
Last Activity: 13 Years ago
by implicit differentiation,(yexy+xexy)dy/dx =1+(2lny)/y,at (0,e),edy/dx=1+(2/e),dy/dx=(1+(2/e))/e, the remaining part of the solution is straightforward.
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