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find the equation of the tangent to the curvee^xy=X+(In y)^2 at the point (0,e)

ilham rafie , 13 Years ago
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saiomkar kandukuri

Last Activity: 12 Years ago

slope of the function or tangent at(0,e) is

dy/dx =(e-1)*e  /2

as we know the point and the slope the equation is y-e =((e-1)e)x))/2

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