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`         Let f(x) and g(x) be two functions which cuts each other orthogonally. At their common point of intersction (x1) , both f(x) and g(x) have equal to n, where n belongs to N, and n ≠ 1. Also if |f ' (x1)| = | g ' (x1)| at the common point of intersection. Then show that the  limit (x approaches x1 )   [f(x).g(x)] is equals to n-1 , where [.] represents greatest integral functions.`
10 years ago

```							Hi,
Since the two functions cut orthogonally,
=>
f'(x1).g'(x1) = -1
Now since
|f ' (x1)| = | g ' (x1)|
Therefore :
f ' (x1)= - g'(x1)
Hence
Either f'(x1) = 1 and g'(x1) = -1
or
f'(x1) = -1 and g'(x1) = 1

Now, What does this statement mean?
"both f(x) and g(x) have ?????? equal to n, where n belongs to N, and n ≠ 1"

Shoould there be something in place of ??????
Rajat
```
10 years ago
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