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f(x)=(4(with power x)-1)(with whole power 3)/ (sine of(x/4))* log(1+x(power2)/3)
is contonuous at x=0?
yes it is continues
f(x)= (4x-1)3
----------------------------
sin(x/4) * log(1+x2/3)
see that by putting x=0 it gives 0/0 form. so U CAN APPLY "L HOSPITAL RULE"(differentiating numerator and denominator independently)
now it is,
3* (4x-1)2 * log4 * 4x
-----------------------------------------------
cos(x/4)*log(1+x2/3)+ sin(x/4)*2/3*1/(x)1/3*1/(1+x2/3)
again 0/0 form by putting x=0...do the same thing as earlier.
it may be long bt this is the concept...keep on differentaing till we get 0/0 form or infinity/infinity form.
other option may be by expanding the gaven things using binomial expansion.
please approve by clicking YES below
at least say yes to the reply yar>.......
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