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show that
limit x tends to (-infinity) (e^x - e^-x)/(e^x + e^-x) = -1
f(x)= (ex-1/ex)/(ex+1/ex)
= (e2x-1)/(e2x+1)
and now simply put the value of .
see that x is negative so e2x will become 1/e2x(number) here the value of x or number is infinity so will gaive infinite value at denominator . 1 diveded by by infinity is almost zero.
so limit becomes -1/1= -1
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