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show thatlimit x tends to (-infinity) (e^x - e^-x)/(e^x + e^-x) = -1

Fawz Naim , 13 Years ago
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Sanjeev Malik IIT BHU

Last Activity: 13 Years ago

f(x)= (ex-1/ex)/(ex+1/ex)

     =  (e2x-1)/(e2x+1)

and now simply put the value of .

see that x is negative so e2x will become 1/e2x(number)    here the value of x or number is infinity so will gaive infinite value at denominator . 1 diveded by by infinity is almost zero.

so limit becomes -1/1=  -1

 

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