Ramesh V
Last Activity: 15 Years ago
we know that sinx lies between [0,1]
for any value of n, 2Pi.n / (3n+1) is not a multiple of Pi/2
so sin(2Pi.n / (3n+1)) can never be equal to 1 , i.e., sin(2Pi.n / (3n+1)) < 1
so the value in this interval [0,1) power infinity gives zero
i.e., the above limi ttends to 0
option A
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Naga Ramesh
IIT Kgp - 2005 batch