d[f(x)]/dx=1/1+x2 => d[f(x)3]/dx=?
a)x square/1+x6
b)x3/1+x6
c)3x2/1+x6
d)3x3/1+x6
Plz explain...
d[f(x)]/dx=1/1+x2 => d[f(x)3]/dx=?
a)x square/1+x6
b)x3/1+x6
c)3x2/1+x6
d)3x3/1+x6
Plz explain...

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