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Lim e x -e -x -2x x-sinx As x tends to zero a)1 b)-1 c)2 d)0 Plz explain.......


Lim ex-e-x-2x


   x-sinx                     As x tends to zero


 


a)1


b)-1


c)2


d)0


Plz explain.......


Grade:

2 Answers

Krishna Kant Tiwari
30 Points
10 years ago

apply l-hospital's rule

ex+e-x-2/(1-cosx)

again apply l-hospital's rule

ex-e-x/sinx 

again apply l-hospital's rule

ex+e-x/cosx

put the limit x tend to zero

we get answer as 2

Answer:2

abhishek ganguly
8 Points
10 years ago

Since it is 0/0 on putting x=0 apply L'Hospital rule  ie  differentiate numerator and denominator with respect to x

Hence we get lim x(tends to 0) (ex + e-x-2)/1-cosx

Again it is 0/0

hence differentiating again we get

lim (ex-e-x)/sinx

Again it is 0/0

so apllying l hospital rule

lim (ex+e-x)/cosx

Now put x=0

we get lim = 2

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