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lim n-infinity (1^n +2^n + 7^n)^1/n

deepak kumar , 14 Years ago

Grade 12

4 Answers

SAGAR SINGH - IIT DELHI

Dear student,

Use L hospital rule in this...

Last Activity: 14 Years ago

Ashwin Sinha

Is it 1???

If Yes, then plz. approve by clicking 'Yes ' given below!! Plz. Plz. Plz.!!!!!!!!

Last Activity: 14 Years ago

fathima x

when u apply the limit directly u get an infinity^0 form ryt.....try takin log and then apply it directly

put the limit=k and den try...

Last Activity: 14 Years ago

jagdish singh singh

$\mathbf{Here } We have to calculate $\mathbf{\lim_{n\to\infty}\left(1^n+2^n+7^n\right)^{\frac{1}{n}}}$\\\\ Taking $\mathbf{7^n}$ Common from that expression, We get\\\\ $\mathbf{\lim_{n\to\infty}7.\left\{(\frac{1}{7})^n+(\frac{2}{7})^n+1\right\}^\frac{1}{n}=7.(0+0+1)^0=7}$

Approved

Last Activity: 14 Years ago

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