AskIITians Expert Hari Shankar IITD
Last Activity: 15 Years ago
Lets assume the statement is true.
log102> 1/5
logxy > z implies that y > xz
Therefore,
2 > 101/5
or 25>(101/5)5 (raising both sides to power 5)
or, 32>10, which is correct.
Now consider the other inequality.
log102< 1/3
Again, logxy > z implies that y > xz
Therefore 2 < 101/3
or, 23>(101/3)3 (raising both sides to power 3)
or, 8>10, which is not true.
Hence, log102> 1/5 is right, but log102< 1/3 does not hold.
So 1/5 < log of 2 to the base 10 < 1/3 is False