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lim (sinx) ^ 1/x ; x is tending to 0 , x>0. how to solve this limit. plz give the full soluntion

lim (sinx) ^ 1/x ; x is tending to 0 , x>0. how to solve this limit.    plz give the full soluntion

Grade:Upto college level

1 Answers

rohan sharma
15 Points
11 years ago

its simple sin x/x ,,,series of sinx is  x-[(x^3)/6]  taking x common u get 1-[(x^2)/2] and now x tends to 0 so x^2 is negligible   

and ans is 1 or 

 

 

       use graph at x→0  (nearly zero) y=x and y= sinx takes same values as y=x is tangent to y=sinx at x=0

 

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