The range of the function f(x)=9^x-3^x+1 is

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vikas askiitian expert · Answer

f(x) = 9 x - 3 x + 1 f(x) = (3 2x ) - 3 x + 1 let 3 x = t f(x) = t 2 - t + 1 f(x) = t 2 - t +1/4 - 1/4 + 1 f(x) = (t-1/2) 2 + 1-1/4 f(x) = (t-1/2) 2 + 3/4 square of any number cannot be less than 0 so minimum value of this function is 3/4 when (t-1/2) 2 = 0 maximum value can be infinity so its range is [3/4 , infinity)

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The range of the function f(x)=9^x-3^x+1 is

The range of the function f(x)=9^x-3^x+1 is

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