Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
Area between the curves Y=sinx and Y=[sinx]from x=0 to x=2pi is Area between the curves Y=sinx and Y=[sinx]from x=0 to x=2pi is
let f(x) , g(x) be the two functions f(x) = sinx g(x) = [sinx] area bw two curves is {f(x) - g(x)}dx lim from 0 to pi A = {sinx - [sinx]}dx lim from 0 to pi A = sinxdx - [sinx]dx lim 0 to pi A = I1 - I2 ..............................1 I1 = sinxdx lim 0 to pi I1 = -cosx lim 0 to pi I1 = -[cospi-cos0] = 2 I2 = [sinx]dx lim 0 to pi = [sinx]dx lim 0 to pi/2 + [sinx]dx lim pi/2 to pi = 0 + 0 = 0 A = I1 - I2 = 2units
let f(x) , g(x) be the two functions
f(x) = sinx
g(x) = [sinx]
area bw two curves is {f(x) - g(x)}dx lim from 0 to pi
A = {sinx - [sinx]}dx lim from 0 to pi
A = sinxdx - [sinx]dx lim 0 to pi
A = I1 - I2 ..............................1
I1 = sinxdx lim 0 to pi
I1 = -cosx lim 0 to pi
I1 = -[cospi-cos0] = 2
I2 = [sinx]dx lim 0 to pi
= [sinx]dx lim 0 to pi/2 + [sinx]dx lim pi/2 to pi
= 0 + 0 = 0
A = I1 - I2 = 2units
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -