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```        let f(x)=(2x-pi)^3 + 2x - cosx
then vlue of d\dx(f^-1(x)) at x=pi is?```
8 years ago

```							Dear student,
d/dx ( 1/f(x) = -f1(x)/f(x)2
f1(x) = 6*(2x-pi)^2 + 2 +sinx
f1(pi) = 6pi2+2
f(pi) = pi^3 + 2pi + 1
d/dx ( 1/f(x) = -f1(x)/f(x)2 at x= pi => -(6pi2+2)/( pi^3 + 2pi + 1)^2
i hope this explains
```
8 years ago
```							but here...f^-1 means inverse function of f.........then what would be the answer?
```
7 years ago
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