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let f(x)=(2x-pi)^3 + 2x - cosx


then vlue of d\dx(f^-1(x)) at x=pi is?

8 years ago

Answers : (2)

Pramod J AskiitiansExpert-IIT-B
36 Points
							

Dear student,

d/dx ( 1/f(x) = -f1(x)/f(x)2

f1(x) = 6*(2x-pi)^2 + 2 +sinx

f1(pi) = 6pi2+2

f(pi) = pi^3 + 2pi + 1

d/dx ( 1/f(x) = -f1(x)/f(x)2 at x= pi => -(6pi2+2)/( pi^3 + 2pi + 1)^2

i hope this explains

8 years ago
ANUVRATHA NARASIMHAN
4 Points
							

but here...f^-1 means inverse function of f.........then what would be the answer?

7 years ago
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