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1. If f'(x) = √2x2 - 1 and y = ƒ(x), then dy/dx at x = 1 is ??
dy/dx is given just put x=1 in that we get f'(1) = root 2 -1
it is given that f'(x) = √2x2-1
dy/dx = f'(x)
so f'(1) = √2(1)2-1 = √2-1 = 1
Final answer is '1'
You can even check this result by applying first principle of differenciation
Please approve !
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