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SIR Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF 1. ROOT SINx 2. (ax + b) to the power n.
1) y = (sinx)1/2 dy/dx = d/dx[(sinx)1/2] = (1/2)(sinx)1/2-1 [d/dx(sinx)] ( d/dx(xn) = nxn-1) =(1/2)(sinx)-1/2(cosx) (d/dx(sinx) =cosx ) 2) y = (ax+b)n dy/dx = d/dx(ax+b)n =n(ax+b)n-1d/dx(ax+b) =n(ax+b)n-1[d/dx(ax) + d/dx(b)] (d/dx(constant) = 0) =n(ax+b)n-1 [a+0] na(ax+b)n-1
1) y = (sinx)1/2
dy/dx = d/dx[(sinx)1/2]
= (1/2)(sinx)1/2-1 [d/dx(sinx)] ( d/dx(xn) = nxn-1)
=(1/2)(sinx)-1/2(cosx) (d/dx(sinx) =cosx )
2) y = (ax+b)n
dy/dx = d/dx(ax+b)n
=n(ax+b)n-1d/dx(ax+b)
=n(ax+b)n-1[d/dx(ax) + d/dx(b)] (d/dx(constant) = 0)
=n(ax+b)n-1 [a+0]
na(ax+b)n-1
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