Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
SIR Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF 1. ROOT SINx 2. (ax + b) to the power n.
1) y = (sinx)1/2 dy/dx = d/dx[(sinx)1/2] = (1/2)(sinx)1/2-1 [d/dx(sinx)] ( d/dx(xn) = nxn-1) =(1/2)(sinx)-1/2(cosx) (d/dx(sinx) =cosx ) 2) y = (ax+b)n dy/dx = d/dx(ax+b)n =n(ax+b)n-1d/dx(ax+b) =n(ax+b)n-1[d/dx(ax) + d/dx(b)] (d/dx(constant) = 0) =n(ax+b)n-1 [a+0] na(ax+b)n-1
1) y = (sinx)1/2
dy/dx = d/dx[(sinx)1/2]
= (1/2)(sinx)1/2-1 [d/dx(sinx)] ( d/dx(xn) = nxn-1)
=(1/2)(sinx)-1/2(cosx) (d/dx(sinx) =cosx )
2) y = (ax+b)n
dy/dx = d/dx(ax+b)n
=n(ax+b)n-1d/dx(ax+b)
=n(ax+b)n-1[d/dx(ax) + d/dx(b)] (d/dx(constant) = 0)
=n(ax+b)n-1 [a+0]
na(ax+b)n-1
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -