SIR
Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF
1. ROOT SINx
2. (ax + b) to the power n.

Question

SIR Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF 1. ROOT SINx 2. (ax + b) to the power n.

vikas askiitian expert · Answer

1) y = (sinx) 1/2 dy/dx = d/dx[(sinx) 1/2 ] = (1/2)(sinx) 1/2-1 [d/dx(sinx)] ( d/dx(x n ) = nx n-1 ) =(1/2)(sinx) -1/2 (cosx) (d/dx(sinx) =cosx ) 2) y = (ax+b) n dy/dx = d/dx(ax+b) n =n(ax+b) n-1 d/dx(ax+b) =n(ax+b) n-1 [d/dx(ax) + d/dx(b)] (d/dx(constant) = 0) =n(ax+b) n-1 [a+0] na(ax+b) n-1

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SIR Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF 1. ROOT SINx 2. (ax + b) to the power n.

SIR
Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF
1. ROOT SINx
2. (ax + b) to the power n.

1 Answers

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