A triangle has two of its vertices at P(a,0) and Q(0,b) and the third vertex R(x,y) is moving along the straight line y=x. If A be the area of triangle, then dA/dx is equal to?
I know the answer it is -(a+b)/2 but I dont know know how to solve the problem.
Plz explain the solution....
A triangle has two of its vertices at P(a,0) and Q(0,b) and the third vertex R(x,y) is moving along the straight line y=x. If A be the area of triangle, then dA/dx is equal to?
I know the answer it is -(a+b)/2 but I dont know know how to solve the problem.
Plz explain the solution....