 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A triangle has two of its vertices at P(a,0) and Q(0,b) and the third vertex R(x,y) is moving along the straight line y=x. If A be the area of triangle, then dA/dx is equal to?

I know the answer it is " -(a+b)/2"  but I dont know know how to solve the problem.

Plz explain the solution....

8 years ago

let R be any point (X,Y)

since this point  lies on line Y = X so

R =(X,X)

p=(a,0)

q=(0,b)

now by determinant method area = 1/2 (determinant)

A   =1/2 [ab - X(a+b)]

differentiating wrt X

dA/dx = 1/2 . -(a+b)

=-(a+b)/2

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Differential Calculus

View all Questions »  Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  Course Features

• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions