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Please solve the following problem, Verify that y = C*e 4x + e 3x , where c is a constant, is a solution to the differential equation y ' - 4y = -e 3x .
Hi Swati please follow the following: y ' is given by y ' = 4C*e 4x + 3e 3x We now substitute y ' and y into the left side of the equation and simplify y ' - 4y = 4C*e 4x + 3e 3x - 4 (C*e 4x + e 3x) = 4C*e 4x + 3e 3x - 4C*e 4x - 4e 3x = 4C*e 4x - 4C*e 4x + e 3x (3 - 4) = - e 3x enjoy...
Hi Swati please follow the following:
y ' is given by y ' = 4C*e 4x + 3e 3x We now substitute y ' and y into the left side of the equation and simplify y ' - 4y = 4C*e 4x + 3e 3x - 4 (C*e 4x + e 3x) = 4C*e 4x + 3e 3x - 4C*e 4x - 4e 3x = 4C*e 4x - 4C*e 4x + e 3x (3 - 4) = - e 3x
enjoy...
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