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1. if lim x9-a9/x-a =lim (4+x),find all possible values of a. x->a x->5
1. if lim x9-a9/x-a =lim (4+x),find all possible values of a.
x->a x->5
x9-a9= (x3)3-(a3)3 =(x3-a3)(x6+a6+(ax)3) =(x-a)(x2+a2+ax)(x6+a6+(ax)3) after putting this ,expression becomes lim x->a (x2+a2+ax)(x6+a6+(ax)3) = lim x->5 (4+x) after taking limit (3a2)(3a6)=9 a8=1 a=-1 or 1 a ns
x9-a9= (x3)3-(a3)3 =(x3-a3)(x6+a6+(ax)3)
=(x-a)(x2+a2+ax)(x6+a6+(ax)3)
after putting this ,expression becomes
lim x->a (x2+a2+ax)(x6+a6+(ax)3) = lim x->5 (4+x)
after taking limit
(3a2)(3a6)=9
a8=1
a=-1 or 1 a ns
POSSIBLE VALUE OF A IS +1 OR -1. BECAUSE FOR FIRST LIMIT THATS GONNA BE 9a8 AND FOR SECOND LIMIT ITS GONNA BE 9. HENCE 9a8=9 a=+1 AND -1 APPROVE MY ANSWER........
POSSIBLE VALUE OF A IS +1 OR -1. BECAUSE FOR FIRST LIMIT THATS GONNA BE 9a8 AND FOR SECOND LIMIT ITS GONNA BE 9. HENCE
9a8=9
a=+1 AND -1
APPROVE MY ANSWER........
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