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Grade Upto college levelDifferential Calculus

1. if lim x9-a9/x-a =lim (4+x),find all possible values of a.

x->a x->5


Profile image of chanda ranjan
15 Years agoGrade Upto college level
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2 Answers

Profile image of vikas askiitian expert
ApprovedApproved Tutor Answer15 Years ago

x9-a9= (x3)3-(a3)3  =(x3-a3)(x6+a6+(ax)3)

                             =(x-a)(x2+a2+ax)(x6+a6+(ax)3)

after putting this ,expression becomes

  lim x->a    (x2+a2+ax)(x6+a6+(ax)3) =  lim x->5  (4+x)

after taking limit

                 (3a2)(3a6)=9

                    a8=1

 a=-1 or 1 a ns

 

Profile image of Souradeep Majumder
15 Years ago

POSSIBLE VALUE OF A IS +1 OR -1.  BECAUSE FOR FIRST LIMIT THATS GONNA BE 9a8 AND FOR SECOND LIMIT ITS GONNA BE 9.  HENCE

 

9a8=9

 

a=+1 AND -1

 

APPROVE MY ANSWER........

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