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Show that the function f defined by f(x) = (1+3x) 1/x when x != 0, f(0) = e 3 is continuous for x = 0 ???
Hi according to me the solution is; limx-->0 f(x) = limx-->0 [(1+3x)1/3x ]3 = e3 = f(0). Thanks.
Hi according to me the solution is;
limx-->0 f(x) = limx-->0 [(1+3x)1/3x ]3 = e3 = f(0).
Thanks.
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