# prove:limit (x) tends to 0 ((sinlog(1+x)/x))=1

Grade:11

## 2 Answers

AKASH GOYAL AskiitiansExpert-IITD
420 Points
13 years ago

Dear Abhik

this is 0/0 form apply L hospital rule

differentiate wrt x

[coslog(1+x)]/(1+x)

put x=0

coslog1/1

cos0= 1

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

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vikas askiitian expert
509 Points
13 years ago

lim x->0 sinlog(1+x)/x

at x=0 ,  0/0 form comes so we can use L holpital rule

differentiating numerator and denominator

after differentiating

limx->0 coslog(1+x) /1+x

=coslog1/1

=cos0=1

hence proved

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