pls solve this:

lim x-0 (1-cosx2^0.5/1-cosx)

1) please reformat the question

2)lim x-0 (1-cosx2^0.5/1-cosx)  in this   wht is this   cosx2^0.5

numerator=1-cosx2^0.5 =sinx denominator=1-cosx by applying lim x-0 we get 0/0(indeterminant form) so we are applying L'phital Rule numerator becomes cosx denominator becomes sinx now by applying lim x-0 we get 1/0=infinity.....which is not indeterminant form