vikas askiitian expert
Last Activity: 14 Years ago
eq of curve is x^1/2 + y^1/2 =a^2
let (x, y,) be the point on the curve at which we have to draw the tangent
since (x, y,) lies on the curve so it will satisfy the eq of curve
so x,^1/2 + y,^1/2 =a^2 ..................eq1
slope of tangent =dy/dx= -(y,/x,)^1/2 at (x, y,)
tangent is equally inclined to axes therefore slope =1 or -1....eq3
solving eq 1 ,2 and 3
required point comes out to be (a^4/4 , a^4/4)