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x3/2+y3/2=A3/2, differentiating both sides w.r.t. x, (3/2)√x +(3/2)√y(dy/dx)=0
dy/dx=-√(x/y), therefore if tangent is equally inclined to axes, mod(dy/dx)=1, in addition,x3/2+y3/2=A3/2, implies that x,y>0, thus, x=y=A(4)-1/3 is the one and only solution
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