Q.1.limx-->infinity(x+2)tan-1(x+2)-xtan-1x
Q.2.limx-->0[{(tan-1x)/x}-{(sin-1x)/x}]1/2
Q.3.limx-->0[{(sin-1x)/x}-{(tan-1x)/x}]1
plz explain properly.
Q.1.limx-->infinity(x+2)tan-1(x+2)-xtan-1x
Q.2.limx-->0[{(tan-1x)/x}-{(sin-1x)/x}]1/2
Q.3.limx-->0[{(sin-1x)/x}-{(tan-1x)/x}]1
plz explain properly.










