The domain of the function

f(x)=[4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}]{to the power1/6} is:

SOLN:

4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}>0

2{to the power 2x}+2{to the power 2(x-2)}-2{to the power 2(x-1)}>52

2{to the power 2x}>64 [HOW?]

Question

The domain of the function

f(x)=[4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}]{to the power1/6} is:

SOLN:

4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}>0

2{to the power 2x}+2{to the power 2(x-2)}-2{to the power 2(x-1)}>52

2{to the power 2x}>64 [HOW?]

Prudhvi teja · Answer

Dear umman

for root1/6 th to exist number should be greater than zero.from that you get first step.

after that its just solving

Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed solution very quickly.

All the best.

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Prudhvi Teja

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