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The domain of the function f(x)=[4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}]{to the power1/6} is: SOLN: 4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)} > 0 2{to the power 2x}+2{to the power 2(x-2)}-2{to the power 2(x-1)} > 52 2{to the power 2x} > 64 [HOW?]

The domain of the function


f(x)=[4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}]{to the power1/6} is:


SOLN:   


4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}>0


2{to the power 2x}+2{to the power 2(x-2)}-2{to the power 2(x-1)}>52


2{to the power 2x}>64   [HOW?]

Grade:12

1 Answers

Prudhvi teja
83 Points
12 years ago

Dear umman

for root1/6 th to exist number should be greater than zero.from that you get first step.

after that its just solving

Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed  solution very  quickly.

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Prudhvi Teja

 

 


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