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The domain of the function f(x)=[4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}]{to the power1/6} is: SOLN: 4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)} > 0 2{to the power 2x}+2{to the power 2(x-2)}-2{to the power 2(x-1)} > 52 2{to the power 2x} > 64 [HOW?]

The domain of the function


f(x)=[4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}]{to the power1/6} is:


SOLN:   


4{to the power x}+8{to the power 2/3(x-2)}-52-2{to the power 2(x-1)}>0


2{to the power 2x}+2{to the power 2(x-2)}-2{to the power 2(x-1)}>52


2{to the power 2x}>64   [HOW?]

Grade:12

1 Answers

Prudhvi teja
83 Points
12 years ago

Dear umman

for root1/6 th to exist number should be greater than zero.from that you get first step.

after that its just solving

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Prudhvi Teja

 

 


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