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Grade 11Differential Calculus

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Profile image of sanket sit
16 Years agoGrade 11
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1 Answer

Profile image of Saineel Sanjay Prabhudessai
16 Years ago

For x<0, f(x)= 1+x3. Therefore g(f(x))= g(1+x3)= (1+x3-1)1/3= x.

for x> or =0, f(x)=x2-1. therefore g(f(x))= g(x2-1)=( x2-1+1)1/2= x.

tore g(f(x))=x for all x belonging to (-infinity,infinity).

 

Thanks,

Saineel.

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