Solve the equation |2x-1| = 3[x] + 2{x} for x

Dear Cathy,

Ans:- When 2x-1>0  i.e x>1/2

then we have

2x-1=2[x]+2{x}+[x]

or 2x-1=2x+[x]

or [x]=-1

Hence  -1<x<0 So no solution in this range.

Again when 2x-1<0 i.e x<1/2 Then we get

       1-2x=2x+[x]

    or 4x+[x]=1

which is possible only when x=1/4 (ans)

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