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The value of limx→∞ ( 2x2 +3 / 2x2 +5 )8x(square) +3 is :-
Hi
The answer is
e-8
y = limx->∞ (2x2+3/2x2+5)8x^2 + 3
take log both side
logy = limx->∞ log (1 - 2/2x2+5)/{1/8x2+3}
Solve it using L Hospitals rule
logy = -8
=> y = e-8
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