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If α is a repeated root of ax2 + bx + c = 0, then Limx→α tan(ax2 + bx + c) / (x - α)2 is ???
Dear Mainak
α is a repeated root of ax2 + bx + c = 0
so ax2 + bx + c=a(x-α)2
now Limx→α tan(ax2 + bx + c) / (x - α)2
=Limx→α [tana(x-α)2 ]/ (x - α)2
=Limx→α a[tana(x-α)2 ]/ a(x - α)2
=a because Limx→0 tanx /x = 1
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